2026 AMC 8 Problem 19: Solution

Work through 2026 AMC 8 Problem 19 on rate problems with a written solution, hints, and a visual explanation.

AlgebraLevel 4 · Challenge

Miguel is walking with his dog, Luna. When they reach the entrance to a park, Miguel throws a ball straight ahead and continues to walk at a steady pace. Luna sprints toward the ball, which stops by a tree. As soon as the dog reaches the ball, she brings it back to Miguel. Luna runs 5 times faster than Miguel walks. What fraction of the distance between the entrance and the tree does Miguel cover by the time Luna brings him the ball?

Miguel walks from the park entrance toward a tree. Luna runs ahead to the tree and then back toward Miguel along the same straight route.
Diagram 1
  • A. 1/6
  • B. 1/5
  • C. 1/4
  • D. 1/3
  • E. 2/5
Hints
  1. Assign a variable to the distance Miguel walks during the whole event, and remember Luna's speed is 5 times his.
  2. Figure out the total distance Luna covers: she runs all the way to the tree, then runs back to meet Miguel partway.
  3. Set Luna's total distance equal to 5 times Miguel's distance and solve for Miguel's distance as a fraction of the distance to the tree.
Read the step-by-step solution

Answer: D · 1/3

  1. Set up variables

    Let Miguel's speed be v and the distance to the tree be d. Luna's speed is 5v. Let x be the distance Miguel walks during the entire event.

  2. Use total distance

    Luna runs d to the tree and then (d − x) back to Miguel, so Luna runs d + (d − x) = 2d − x. Since Luna runs 5x in the same time Miguel walks x: 5x = 2d − x, giving 6x = 2d, so x = d/3.

    6x = 2d → x = d/3

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